Difference between revisions of "Excluding bichromatic vertices"

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'''Theorem 1'''  A 4-coloring of the unit plane cannot contain a bichromatic vertex (a vertex that can be colored in either of two colors while keeping the color of all other vertices fixed).
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'''Proof'''
  
 
[[Category:Polymath16]]
 
[[Category:Polymath16]]

Revision as of 10:00, 10 May 2018

Theorem 1 A 4-coloring of the unit plane cannot contain a bichromatic vertex (a vertex that can be colored in either of two colors while keeping the color of all other vertices fixed).

Proof