# Difference between revisions of "Sylvester's sequence"

(New page: Sylvester's sequence <math>a_1,a_2,a_3,\ldots</math> is defined recursively by setting <math>a_1=2</math> and <math>a_k = a_1 \ldots a_{k-1}+1</math> for all subsequent k, thus the sequenc...) |
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− | Sylvester's sequence <math>a_1,a_2,a_3,\ldots</math> is defined recursively by setting <math>a_1=2</math> and <math>a_k = a_1 \ldots a_{k-1}+1</math> for all subsequent k, thus the sequence begins | + | '''Sylvester's sequence''' <math>a_1,a_2,a_3,\ldots</math> is defined recursively by setting <math>a_1=2</math> and <math>a_k = a_1 \ldots a_{k-1}+1</math> for all subsequent k, thus the sequence begins |

− | : 2, 3, 7, 43, 1807, 3263443, 10650056950807, 113423713055421844361000443 (sequence A000058 in OEIS). | + | : 2, 3, 7, 43, 1807, 3263443, 10650056950807, 113423713055421844361000443 (sequence [http://www.research.att.com/~njas/sequences/A000058 A000058] in OEIS). |

The elements of this sequence are mutually coprime, so after factoring k of them, one is guaranteed to have at least k prime factors. | The elements of this sequence are mutually coprime, so after factoring k of them, one is guaranteed to have at least k prime factors. | ||

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It is also conjectured that this sequence is square-free; if so, <math>a_k, a_k-1</math> form a pair of square-free integers, settling a toy problem in the finding primes project. | It is also conjectured that this sequence is square-free; if so, <math>a_k, a_k-1</math> form a pair of square-free integers, settling a toy problem in the finding primes project. | ||

− | + | * [[wikipedia:Sylvester's_sequence|The Wikipedia entry for this sequence]] |

## Revision as of 15:58, 19 August 2009

**Sylvester's sequence** [math]a_1,a_2,a_3,\ldots[/math] is defined recursively by setting [math]a_1=2[/math] and [math]a_k = a_1 \ldots a_{k-1}+1[/math] for all subsequent k, thus the sequence begins

- 2, 3, 7, 43, 1807, 3263443, 10650056950807, 113423713055421844361000443 (sequence A000058 in OEIS).

The elements of this sequence are mutually coprime, so after factoring k of them, one is guaranteed to have at least k prime factors.

There is a connection to the finding primes project: It is a result of Odoni that the number of primes less than n that can divide any one of the [math]a_k[/math] is [math]O(n / \log n \log\log\log n)[/math] rather than [math]O(n / \log n)[/math] (the prime number theorem bound). If we then factor the first k elements of this sequence, we must get a prime of size at least [math]k\log k \log \log \log k[/math] or so.

It is also conjectured that this sequence is square-free; if so, [math]a_k, a_k-1[/math] form a pair of square-free integers, settling a toy problem in the finding primes project.