# Difference between revisions of "Verify the bounded discrepancy of an input sequence"

From Polymath1Wiki

Yangofzeal (Talk | contribs) m (added a link back to the original referring page) |
Yangofzeal (Talk | contribs) |
||

Line 23: | Line 23: | ||

def verifySequence(x, C=2, verbose=False): | def verifySequence(x, C=2, verbose=False): | ||

− | """verify discrepancy <= | + | """verify discrepancy <= C |

""" | """ |

## Latest revision as of 18:43, 11 January 2010

back to the main experimental results page.

#!/usr/bin/env python """Erdos Discrepancy Problem sequence verification. Verifies that discrepancy is bounded for 1124-length sequence of +/-1. file 1124_min.txt should contain: + - + + - - - - ... by Michael Yang, 2010 """ from __future__ import with_statement from numpy import zeros, int8 SEQUENCE_LENGTH = 1124 fileInput = '1124_min.txt' class DiscrepancyError(Exception): pass def verifySequence(x, C=2, verbose=False): """verify discrepancy <= C """ for i in range(SEQUENCE_LENGTH): inds = range(i,SEQUENCE_LENGTH,i+1) s = x[inds].sum() # discrepancy if abs(s) > C: msg = 'd = %d has discrepancy %s' msg %= (i+1, s) raise DiscrepancyError(msg) if verbose: print i+1, s if verbose: print 'verified' return True if __name__=='__main__': # load +/- sequence x = zeros(SEQUENCE_LENGTH, dtype = int8) with open(fileInput, 'r') as f: a = f.read() for i, side in enumerate(a.strip().split()): if side == '-': x[i] = -1 elif side == '+': x[i] = 1 assert i == SEQUENCE_LENGTH - 1 isGood = verifySequence(x)