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	<updated>2026-06-23T10:27:09Z</updated>
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		<id>https://michaelnielsen.org/polymath/index.php?title=Other_proposed_projects&amp;diff=5039</id>
		<title>Other proposed projects</title>
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		<updated>2011-10-24T21:14:13Z</updated>

		<summary type="html">&lt;p&gt;Squark: Added my quantum cellular automata proposal&lt;/p&gt;
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&lt;div&gt;This page is a repository for any polymath proposals which are not fleshed out enough to have their own separate posts for the proposal.  Contributions are welcome.&lt;br /&gt;
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== Beating the trivial subset sum algorithm ==&lt;br /&gt;
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This problem was proposed by Ernie Croot, though he would not have the time to run a project based on this problem.&lt;br /&gt;
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It is a problem that is easy to state, probably will succumb to elementary methods, and probably could be solved if enough people contributed ideas. Here goes: consider the usual subset sum (or is it knapsack?) problem where you are given a list of positive integers N_1, …, N_k, and a target number T, and you must decide whether there is some subset of N_1, …, N_k that sums to T. The problem is to beat the “trivial algorithm”, which I shall describe presently.&lt;br /&gt;
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The first thing to realize is that there is a subset sum equal to T iff there is one equal to S-T, where S=N_1 + … + N_k. Furthermore, subsets of size t summing to T correspond uniquely to subsets of size k-t summing to S-T. In this way, you only need to consider subsets of size at most k/2 (and check whether they sum of T or S-T) to solve the problem. But now you can use the usual “collision technique” to reduce the problem to subsets of size at most k/4, by forming a table of all subsets of at most this size, along with their sum of elements, until you find a disjoint pair of subsets that sums to either T or S-T. The running time of this procedure should be comparable to (k choose k/4) = c^(k+o(k)), for a certain constant c that is easy to work out. This is what I mean by the “trivial algorithm”. Now, the problem is find an algorithm — any at all — that runs in time at most d^k, where d &amp;lt; c. To my knowledge no such algorithm is know to exist!&lt;br /&gt;
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== Filters on posets and generalizations ==&lt;br /&gt;
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I suggest to collaboratively finish writing my draft &amp;quot;Filters on posets and generalizations&amp;quot;.&lt;br /&gt;
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See [http://filters.wikidot.com/ this wiki].&lt;br /&gt;
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Note that this manuscript contains [http://portonmath.wordpress.com/2009/07/31/complementive-complete-lattice/ this conjecture] which can be separated into an other smaller polymath project.&lt;br /&gt;
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== Coupling determinantal processes ==&lt;br /&gt;
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Any n-dimensional subspace V of a Euclidean space &amp;lt;math&amp;gt;{\Bbb R}^N&amp;lt;/math&amp;gt; gives rise to a random subset A_V of {1,...,N}, with the probability that &amp;lt;math&amp;gt;A_V = \{i_1,\ldots,i_k\}&amp;lt;/math&amp;gt; being the square of the magnitude of the projection of &amp;lt;math&amp;gt;e_{i_1} \wedge \ldots \wedge e_{i_n}&amp;lt;/math&amp;gt; to V. This is known as the determinantal process associated to V.&lt;br /&gt;
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If V is a subspace of W, it is known that one can couple &amp;lt;math&amp;gt;A_V&amp;lt;/math&amp;gt; to &amp;lt;math&amp;gt;A_W&amp;lt;/math&amp;gt; in such a way that the former set is a subset of the latter, but no &amp;quot;natural&amp;quot; way of doing this is known.  One problem in this project would be to find such a natural way.&lt;br /&gt;
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A related problem: if V, W are orthogonal, is it always possible to couple &amp;lt;math&amp;gt;A_V, A_W, A_{V+W}&amp;lt;/math&amp;gt; together in such a way that &amp;lt;math&amp;gt;A_{V + W} = A_V \cup A_W&amp;lt;/math&amp;gt;?&lt;br /&gt;
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These questions are raised in page 38 of [http://uk.arxiv.org/PS_cache/math/pdf/0204/0204325v4.pdf this paper of Lyons], and also discussed at [http://terrytao.wordpress.com/2009/08/23/determinantal-processes/ this blog post].&lt;br /&gt;
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== Stable commutator length in the free group ==&lt;br /&gt;
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Let G be the free group on two generators, and let [G,G] be the commutator subgroup.  Given any g in [G,G], the commutator length cl(g) is the least number of commutators needed to express g, and the stable commutator length scl(g) is the lim of cl(g^n)/n.&lt;br /&gt;
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It is known that scl(g) &amp;gt;= 1/2 for any non-trivial g.  Find a combinatorial proof of this fact.&lt;br /&gt;
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It is conjectured that { scl(g): g in [G,G] } has an isolated point at 1/2.  Prove this.&lt;br /&gt;
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Reference: scl, Danny Calegari&lt;br /&gt;
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== Quantum cellular automata ==&lt;br /&gt;
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The proposal is tackling [http://mathoverflow.net/questions/78707/are-all-quantum-cellular-automata-invertible-representable these 2 questions].&lt;/div&gt;</summary>
		<author><name>Squark</name></author>
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