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	<id>https://michaelnielsen.org/polymath/index.php?action=history&amp;feed=atom&amp;title=Side_Proof_1</id>
	<title>Side Proof 1 - Revision history</title>
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	<updated>2026-06-29T14:32:09Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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	<entry>
		<id>https://michaelnielsen.org/polymath/index.php?title=Side_Proof_1&amp;diff=9627&amp;oldid=prev</id>
		<title>Tomtom2357: Created page with &quot;This page will handle one of the long cases in the Human proof that completely multiplicative sequences have discrepancy greater than 3, so that the page can be shorter an...&quot;</title>
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		<updated>2015-05-21T09:26:26Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;This page will handle one of the long cases in the &lt;a href=&quot;/polymath/index.php?title=Human_proof_that_completely_multiplicative_sequences_have_discrepancy_greater_than_3&quot; title=&quot;Human proof that completely multiplicative sequences have discrepancy greater than 3&quot;&gt;Human proof that completely multiplicative sequences have discrepancy greater than 3&lt;/a&gt;, so that the page can be shorter an...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;This page will handle one of the long cases in the [[Human proof that completely multiplicative sequences have discrepancy greater than 3]], so that the page can be shorter and not have so many long sections. Specifically, this page will take care of the case where we assume: f(2)=f(7)=f(19)=f(23)=f(29)=1.&lt;br /&gt;
&lt;br /&gt;
Looking at the table:&lt;br /&gt;
&lt;br /&gt;
 0 1 2 3 4 5 6 7 8 9&lt;br /&gt;
&lt;br /&gt;
 0|+ + - + - - + + +   0-9&lt;br /&gt;
 - - - - + + + - + +   10-19&lt;br /&gt;
 - - - + - + - - +|+   20-29&lt;br /&gt;
 + ? + + - - + ? + +   30-39&lt;br /&gt;
 - ? - ? - - + ? - +   40-49&lt;br /&gt;
 + + - ? - + + - + ?   50-59&lt;br /&gt;
 + ? ? + + + + ? - -   60-69&lt;br /&gt;
&lt;br /&gt;
We can first see that the discrepancy up to 32 is 3+f(31), so f(31)=-1. Also, there is a cut after 64, because of f[63,66].&lt;br /&gt;
&lt;br /&gt;
 0 1 2 3 4 5 6 7 8 9&lt;br /&gt;
&lt;br /&gt;
 0|+ + - + - - + + +   0-9&lt;br /&gt;
 - - - - + + + - + +   10-19&lt;br /&gt;
 - - - + - + - - +|+   20-29&lt;br /&gt;
 + - + + - - + ? + +   30-39&lt;br /&gt;
 - ? - ? - - + ? - +   40-49&lt;br /&gt;
 + + - ? - + + - + ?   50-59&lt;br /&gt;
 + ? - + +|+ + ? - -   60-69&lt;br /&gt;
&lt;br /&gt;
Now the discrepancy up to 38 is 3+f(37), therefore f(37)=-1.&lt;br /&gt;
&lt;br /&gt;
 0 1 2 3 4 5 6 7 8 9&lt;br /&gt;
&lt;br /&gt;
 0|+ + - + - - + + +   0-9&lt;br /&gt;
 - - - - + + + - + +   10-19&lt;br /&gt;
 - - - + - + - - +|+   20-29&lt;br /&gt;
 + - + + - - + - + +   30-39&lt;br /&gt;
 - ? - ? - - + ? - +   40-49&lt;br /&gt;
 + + - ? - + + - + ?   50-59&lt;br /&gt;
 + ? - + +|+ + ? - -   60-69&lt;br /&gt;
&lt;br /&gt;
Here is where things start to get interesting. The discrepancy up to 64, which is 4+f(41)+f(43)+f(47)+f(53)+f(59)+f(61), must be zero because of the cut. Therefore exactly one of f(41), f(43), f(47), f(53), f(59), f(61) must be 1, and the others -1. However, the discrepancy f[243,248] = -4-f(41)+f(61), so if f(41) = 1, f(61) must be -1, but then the discrepancy f[243,248] = -6, forcing the discrepancy to be greater than 3. Therefore f(41)=-1.&lt;br /&gt;
&lt;br /&gt;
 0 1 2 3 4 5 6 7 8 9&lt;br /&gt;
&lt;br /&gt;
 0|+ + - + - - + + +   0-9&lt;br /&gt;
 - - - - + + + - + +   10-19&lt;br /&gt;
 - - - + - + - - + +   20-29&lt;br /&gt;
 + - + + - - + - + +   30-39&lt;br /&gt;
 - - -|? - - + ? - +   40-49&lt;br /&gt;
 + + - ? - + + - + ?   50-59&lt;br /&gt;
 + ? - + +|+ + ? - -   60-69&lt;br /&gt;
 - ? + ? - - + - + ?   70-79&lt;br /&gt;
 - + - ? - + ? - - ?   80-89&lt;br /&gt;
 - - + + ? - - ? + -   90-99&lt;br /&gt;
 &lt;br /&gt;
Now, if f(43) = 1, then f(61)=-1, and considering f[243,250] = -5-f(83), we have also that f(83)=-1. Also, f(47)=f(53)=f(59)=f(61)=-1, and the table would look like this:&lt;br /&gt;
&lt;br /&gt;
 0 1 2 3 4 5 6 7 8 9&lt;br /&gt;
&lt;br /&gt;
 0|+ + - + - - + + +   0-9&lt;br /&gt;
 - - - - + + + - + +   10-19&lt;br /&gt;
 - - - + - + - - + +   20-29&lt;br /&gt;
 + - + + - - + - + +   30-39&lt;br /&gt;
 - - -|+ - - + - - +   40-49&lt;br /&gt;
 + + - - - + + - + -   50-59&lt;br /&gt;
 + - - + +|+ + ? - -   60-69&lt;br /&gt;
 - ? + ? - - + - + ?   70-79&lt;br /&gt;
 - + - - - + + - - ?   80-89&lt;br /&gt;
 - - + + - - - ? + -   90-99&lt;br /&gt;
&lt;br /&gt;
The discrepancy up to 96 is now -7+f(67)+f(71)+f(73)+f(79)+f(89). Therefore f(67)=f(71)=f(73)=f(79)=f(89)=1. If we now say that f(107)=a, f(109)=b, f(163)=c, f(167)=d, f(331)=e. We have three choke points to consider here. First, f[155,172] = 5+f(157)+c+d, which implies that c+d&amp;lt;=0. Second, f[213,218] = -4+a+b implies that a+b&amp;gt;=0. Third, f[319,334]=-7-a-b+c+d+e. Plugging the results from the first two equations in, we get that f[319,334]&amp;lt;=-7+e, which is impossible, since that would force the discrepancy to be greater than 3.&lt;br /&gt;
&lt;br /&gt;
Therefore f(43) = -1. The table is now:&lt;br /&gt;
&lt;br /&gt;
 0 1 2 3 4 5 6 7 8 9&lt;br /&gt;
&lt;br /&gt;
 0|+ + - + - - + + +   0-9&lt;br /&gt;
 - - - - + + + - + +   10-19&lt;br /&gt;
 - - - + - + - - + +   20-29&lt;br /&gt;
 + - + + - - + - + +   30-39&lt;br /&gt;
 - - -|- - - + ? - +   40-49&lt;br /&gt;
 + + - ? - + + - + ?   50-59&lt;br /&gt;
 + ? - + +|+ + ? - -   60-69&lt;br /&gt;
 - ? + ? - - + - + ?   70-79&lt;br /&gt;
 - + - ? - + - - - ?   80-89&lt;br /&gt;
 - - + + ? - - ? + -   90-99&lt;br /&gt;
&lt;br /&gt;
The discrepancy up to 48 is now -3-f(47), so f(47)=1. Therefore, f(53)=f(59)=f(61)=-1. But now, f[183,188]=6, which is a contradiction.&lt;br /&gt;
&lt;br /&gt;
Therefore f(29)=-1.&lt;/div&gt;</summary>
		<author><name>Tomtom2357</name></author>
	</entry>
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