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\section{Passing between probability measures}
\section{Passing between probability measures} \label{sec:measures}


\noteryan{As mentioned at the end, I think this section would be better if the master lemma at the end came first}
The goal of this section is to work out bounds for the error arising when passing back and forth between $\unif_k$ and $\ens{k}$, as described in Section~\ref{sec:outline-dist}.  Lemma~\ref{lem:distributions} below gives the bounds we need.  The reader will not lose much by just reading its statement; the proof is just technical calculations.


Before stating Lemma~\ref{lem:distributions} we need some definitions.


\subsection{Comparing product distributions}
\ignore{
\begin{definition} Given a set $A \subseteq [k]^n$ and a restriction $(J,x_\barJ)$, we write $A_{x_\barJ}$ for the subset of $[k]^{J}$ defined by $A_{x_\barJ} = \{y \in [k]^J : (x_{\barJ}, y_J) \in A\}$.
\end{definition}}
 
\begin{definition} \label{def:r4r} For $0 \leq \ppn \leq 1$, we say that $J$ is a \emph{$\ppn$-random subset} of $[n]$ if $J$ is formed by including each coordinate $i \in [n]$ independently with probability $\ppn$.  Assuming $r \leq n/2$, we say that $J$ is an \emph{$[r,4r]$-random subset} of $[n]$ if $J$ is a $\ppn$-random subset of $[n]$ conditioned on $r \leq \abs{J} \leq 4r$, with $\ppn = 2r/n$.
\end{definition}
\begin{definition} A \emph{distribution family} $(\distra^m)_{m \in \N}$ (over $[k]$) is a sequence of probability distributions, where $\distra^m$ is a distribution on $[k]^m$.  In this paper the families we consider will either be the equal-(nondegenerate-)slices family $\distra^m = \ens{k}^m$ or $\distra^m = \eqs{k}^m$, or will be the product distributions based on a single distribution $\prd$ on $[k]$, $\distra^m = \prd^{\otimes m}$.
\end{definition}


We begin by recording some simple facts about distances between probability distributions.  Throughout this subsection we assume $\pi$ and $\nu$ are probability distributions on the same finite set $\Omega$.\noteryan{Perhaps change $\Omega$ to $[k]$ throughout.} 


\begin{fact}  \label{fact:tv-mix} Let $(\nu_\kappa)_{\kappa \in K}$ be a family of distributions on $\Omega$, let $\lambda$ be a distribution on $K$, and let $\mu$ be the associated mixture distribution, given by drawing $\kappa \sim \lambda$ and then drawing from $\nu_\kappa$.  Then\noteryan{need to prove? It's just the triangle inequality}
\begin{lemma}  \label{lem:distributions} Let $(\distra^m)$ and $(\distrb^m)$ be distribution families.  Assume $2 \ln n \leq r \leq n/2$.  Let $J$ be an $[r,4r]$-random subset of $[n]$, let $x$ be drawn from $[k]^{\barJ}$ according to $\distra^{\abs{\barJ}}$, and let $y$ be drawn from $[k]^J$ according to $\distrb^{\abs{J}}$.  The resulting distribution on the composite string $(x,y) \in [k]^n$ has total variation distance from $\distra^n$ which can be bounded as follows:
\begin{enumerate}
\item (Product to equal-slices.)  \label{eqn:distrs-prd-eqs} If $\distra^m = \prd^{\otimes m}$ and $\distrb^m = \eqs{\ell}^m$ for $\ell \leq k$, the bound is \noteryan{You know, we only need this result for the uniform distribution, in which case we can bound the below by the simpler $2k \cdot r/\sqrt{n}$.}
\[
\[
\dtv{\pi}{\mu} \leq \Ex_{\kappa \sim \lambda}[\dtv{\pi}{\nu_\kappa}].
(2{\textstyle \sqrt{\frac{1}{\min(\prd)}-1}})+2) \cdot r / \sqrt{n}.
\]
\]
\end{fact}
\item (Equal-slices to product.) \label{eqn:distrs-eqs-prd} If $\distra^m = \eqs{k}^m$ and $\distrb^m = \prd^{\otimes m}$, the bound is $4k \cdot r/\sqrt{n}$, independent of $\prd$.
\begin{definition}
\item (Equal-slices to equal-slices.) \label{eqn:distrs-eqs-eqs} If $\distra^m = \eqs{k}^m$ and $\distrb^m = \eqs{\ell}^m$ for $\ell \leq k$, the bound is $4k \cdot r/\sqrt{n}$.
The \emph{$\chi^2$ distance} $\dchi{\pi}{\nu}$ is defined by\noteryan{I assume the reader is savvy enough to realize we mean to take the positive square root\dots}
\end{enumerate}
\end{lemma}
 
Although Lemma~\ref{lem:distributions} involves the equal-slices distribution, one can convert to equal-nondegenerate-slices if desired using Proposition~\ref{prop:degen}.
 
 
Since $\eqs{k}^n$ is a mixture of product distributions (Proposition~\ref{prop:eqs-mix}), the main work in proving Lemma~\ref{lem:distributions} involves comparing product distributions.
 
 
\subsection{Comparing product distributions}
\begin{definition}   For $\distra$ and $\distrb$ probability distributions on $\Omega^n$, the \emph{$\chi^2$ distance} $\dchi{\pi}{\nu}$ is defined by
\[
\[
\dchi{\pi}{\nu}^2 = \Varx_{x \sim \pi}\left[\frac{\nu[x]}{\pi[x]}\right].
\dchi{\distra}{\distrb} = \sqrt{\Varx_{x \sim \distra}\left[\frac{\distrb[x]}{\distra[x]}\right]}.
\]
\]
Note that $\dchi{\pi}{\nu}$ is \emph{not} symmetric in $\pi$ and $\nu$.
Note that $\dchi{\distra}{\distrb}$ is \emph{not} symmetric in $\distra$ and $\distrb$.
\end{definition}
\end{definition}


The $\chi^2$ distance is introduced to help us prove the following fact:
The $\chi^2$ distance is introduced to help us prove the following fact:
\begin{proposition} \label{prop:mix-distance} Assume $\min(\pi) \neq 0$; i.e., $\pi$ has full support. Suppose $\pi$ is slightly mixed with~$\nu$, forming $\hat{\pi}$; specifically, $\hat{\pi} = (1-\eps) \pi + \eps \nu$.  Then the associated product distributions $\pi^{\otimes n}$, $\hat{\pi}^{\otimes n}$ on $\Omega^{n}$ satisfy
\begin{proposition} \label{prop:mix-distance} Let $\prd$ be a distribution on $\Omega$ with full support; i.e., $\min(\pi) \neq 0$. Suppose $\prd$ is slightly mixed with $\distrb$, forming $\wh{\prd}$; specifically, $\wh{\prd} = (1-\ppn) \prd + \ppn \distrb$.  Then the associated product distributions $\prd^{\otimes n}$, $\wh{\prd}^{\otimes n}$ on $\Omega^{n}$ satisfy
\[
\[
\dtv{\pi^{\otimes n}}{\hat{\pi}^{\otimes n}} \leq \dchi{\pi}{\nu} \cdot \eps \sqrt{n}.
\dtv{\prd^{\otimes n}}{\wh{\prd}^{\otimes n}} \leq \dchi{\prd}{\distrb} \cdot \ppn \sqrt{n}.
\]
\]
\end{proposition}
\end{proposition}
\begin{proof}  It is a straightforward consequence of Cauchy-Schwarz (see, e.g.~\cite[p.\ 101]{Rei89})\noteryan{This is the part using $\min(\pi) \neq 0$, by the way.} that  
\begin{proof}  It is a straightforward consequence of Cauchy-Schwarz (see, e.g.~\cite[p.\ 101]{Rei89})\noteryan{This is the part using $\min(\prd) \neq 0$, by the way.} that  
\[
\[
\dtv{\pi^{\otimes n}}{\hat{\pi}^{\otimes n}} \leq \dchi{\pi}{\hat{\pi}} \cdot \sqrt{n},
\dtv{\prd^{\otimes n}}{\wh{\prd}^{\otimes n}} \leq \dchi{\prd}{\wh{\prd}} \cdot \sqrt{n},
\]
\]
and the identity $\dchi{\pi}{\hat{\pi}} = \eps \dchi{\pi}{\nu}$ follows easily from the definitions.
and the identity $\dchi{\prd}{\wh{\prd}} = \ppn \cdot \dchi{\prd}{\distrb}$ follows easily from the definitions.
\end{proof}
\end{proof}
This can be bounded independently of $\nu$, as follows:
This can be bounded independently of $\distrb$, as follows:
\begin{corollary} \label{cor:mix-distance} In the setting of Proposition~\ref{prop:mix-distance},  
\begin{corollary} \label{cor:mix-distance} In the setting of Proposition~\ref{prop:mix-distance},  
\[
\[
\dtv{\pi^{\otimes n}}{\hat{\pi}^{\otimes n}} \leq \sqrt{{\textstyle \frac{1}{\min(\pi)}} - 1} \cdot \eps \sqrt{n},
\dtv{\prd^{\otimes n}}{\wh{\prd}^{\otimes n}} \leq \sqrt{{\textstyle \frac{1}{\min(\prd)}} - 1} \cdot \ppn \sqrt{n},
\]
\]
\end{corollary}
\end{corollary}
\begin{proof}  It is easy to check that the distribution $\nu$ maximizing $\dchi{\pi}{\nu}$ is the one putting all its mass on the $x$ minimizing $\pi[x]$.  In this case one calculates $\dchi{\pi}{\nu} = \sqrt{\frac{1}{\min(\pi)} - 1}$.
\begin{proof}  It is easy to check that the distribution $\distrb$ maximizing $\dchi{\prd}{\distrb}$ is the one putting all its mass on the $x$ minimizing $\prd[x]$.  In this case one calculates $\dchi{\prd}{\distrb} = \sqrt{\frac{1}{\min(\pi)} - 1}$.
\end{proof}
\end{proof}


Line 45: Line 64:




\subsection{Restrictions and composite distributions}


\begin{definition} A \emph{restriction} on $[k]^n$ is a pair $(J, x_\barJ)$, where $J \subseteq [n]$ and $x_\barJ \in [k]^{\barJ}$, where $\barJ = [n] \setminus J$.  It is thought of as a ``partial string'', where the $\barJ$-coordinates are ``fixed'' according to $x_\barJ$ and the $J$-coordinates are still ``free''.  Given a fixing $y_J \in [k]^J$, we write $(x_\barJ, y_J)$ for the complete composite string in $[k]^n$.\noteryan{Although this notation looks awkward, I believe it's useful.  Also, I suppose we should point out that a restriction is a special kind of combinatorial subspace.}
\subsection{Proof of Lemma~\ref{lem:distributions}}
\end{definition}


\begin{definition} Given a set $A \subseteq [k]^n$ and a restriction $(J,x_\barJ)$, we write $A_{x_\barJ}$ for the subset of $[k]^{J}$ defined by $A_{x_\barJ} = \{y \in [k]^J : (x_{\barJ}, y_J) \in A\}$.
\end{definition}


\begin{definition} If $0 \leq \eps \leq 1$, we say that $J$ is an \emph{$\eps$-random subset} of $[n]$ if $J$ is formed by including each coordinate $i \in [n]$ independently with probability $\eps$.   
\begin{definition} \label{def:compos-distr} Let $0 \leq \ppn \leq 1$ and let $(\distra^m)$, $(\distrb^m)$ be distribution families. Drawing from the \emph{$(\ppn, \distra, \distrb)$-composite distribution} on $[k]^n$ entails the following: $J$ is taken to be a $\ppn$-random subset of~$[n]$; $x$ is drawn from $[k]^{\barJ}$ according to $\distra^{\abs{\barJ}}$; and, $y$ is drawn from $[k]^J$ according to $\distrb^{\abs{J}}$.  We sometimes think of this distribution as just being a distribution on composite strings $z = (x, y) \in [k]^n$.
\end{definition}
\end{definition}


\begin{definition} \label{def:rand-restriction} Let $0 \leq \eps \leq 1$ and let $(\pi^m)$ be a family of probability distributions, where $\pi^m$ is a distribution on $[k]^m$. An \emph{$(\epsilon,\pi)$-random restriction} $(J, x_\barJ)$ is formed by letting $J$ be an $\eps$-random subset of $[n]$ and then drawing $x_\barJ$ from $[k]^{\barJ}$ according to $\pi^{|\barJ|}$.
Note that the distribution described in Lemma~\ref{lem:distributions} is very similar to the $(\ppn, \distra, \distrb)$-composite distribution, except that it uses an $[r, 4r]$-random subset rather than a $\ppn$-random subset. We can account for this difference with a standard Chernoff (large-deviation) bound:\noteryan{Citation needed?}
\end{definition}
\begin{fact}  \label{fact:dev} If $J$ is a $\ppn$-random subset of $[n]$ with $\ppn = 2r/n$ as in Definition~\ref{def:r4r}, then $r \leq \abs{J} \leq 4r$ holds except with probability at most $2\exp(-r/4)$.
In the above definition, $\pi^m$ will either be equal-slices $\eqs{k}^m$ or a product distribution $\nu^{\otimes m}$ based on some distribution $\nu$ on $[k]$. 
\end{fact}


\begin{definition}  In the setting of Definition~\ref{def:rand-restriction}, suppose that $(\nu^m)$ is another family of distributions.  The \emph{$(\eps, \pi, \nu)$-composite distribution} generates an $(\eps,\pi)$-random restriction $(J, x_\barJ)$ and then generates $y_J \in [k]^J$ according to $\nu^{|J|}$.  We sometimes think of this distribution as just being a distribution on composite strings $z = (x_\barJ, y_J) \in [k]^n$.
The utility of using $\ppn$-random subsets in Definition~\ref{def:compos-distr} is the following observation:
\end{definition}
\begin{fact}  If $\prd$ and $\distrb$ are distributions on $[k]$, thought of also as product distribution families, then the $(\ppn, \prd, \distrb)$-composite distribution on $[k]^n$ is precisely the product distribution $\wh{\prd}^{\otimes n}$, where $\wh{\prd}$ is the mixture distribution $(1-\ppn)\prd + \ppn \distrb$ on $[k]$.
 
\begin{fact}  If $\pi$ and $\nu$ are distributions on $[k]$, thought of also as product distribution families, then the $(\eps, \pi, \nu)$-composite distribution on $[k]^n$ is precisely the product distribution $\hat{\pi}^{\otimes n}$, where $\hat{\pi}$ is the mixture distribution $(1-\eps)\pi + \eps \nu$ on $[k]$.
\end{fact}
\end{fact}


Because of this, we can use Corollary~\ref{cor:mix-distance} to bound the total variation distance between $\pi^{\otimes n}$ and a composite distribution.  We conclude:
Because of this, we can use Corollary~\ref{cor:mix-distance} to bound the total variation distance between $\prd^{\otimes n}$ and a composite distribution.  We conclude:
\begin{proposition}  \label{prop:prod-composite} Let $\prd$ and $\distrb$ be any distributions on $[k]$, thought of also as product distribution families.  Writing $\wt{\prd}$ for the $(\ppn,\prd,\distrb)$-composite distribution on strings in $[k]^n$, we have
\[
\dtv{\prd^{\otimes n}}{\wt{\prd}} \leq {\textstyle \sqrt{\frac{1}{\min(\prd)}-1}} \cdot \ppn \sqrt{n}.
\]
\end{proposition}


\begin{proposition} \label{prop:prod-composite} Let $\pi$ and $\nu$ be any distributions on $[k]$.  Writing $\wt{\pi}$ for the $(\eps,\pi,\nu)$-composite distribution on strings in $[k]^n$, we have
Recall that for any $\ell \leq k$, the equal-slices distribution $\eqs{\ell}^{m}$ on $m$ coordinates is a mixture of product distributions $\spac^{\otimes m}$ on $[k]^m$.  We can therefore average Proposition~\ref{prop:prod-composite} over $\distrb$ to obtain:
\begin{proposition}  \label{prop:prod-eqs} If $\wt{\pi}$ denotes the $(\ppn,\pi,\eqs{\ell})$-composite distribution on strings in $[k]^n$, where $\ell \leq k$, then we have
\[
\[
\dtv{\pi^{\otimes n}}{\wt{\pi}} \leq {\textstyle \sqrt{\frac{1}{\min(\pi)}-1}} \cdot \eps \sqrt{n}.
\dtv{\pi^{\otimes n}}{\wt{\pi}} \leq {\textstyle \sqrt{\frac{1}{\min(\pi)}-1}} \cdot \ppn \sqrt{n}.
\]
\]
\end{proposition}
\end{proposition}
For any $\ell \leq k$, the equal-slices distribution $\eqs{\ell}^{m}$ on $m$ coordinates is a mixture of product distributions $\nu^{\otimes m}$ on $[k]^m$.  In light of Fact~\ref{fact:tv-mix}, we can average Proposition~\ref{prop:prod-composite} over $\nu$ to obtain:
Here we have used the following basic bound, based on the triangle inequality:
\begin{proposition}  \label{prop:prod-eqs} If $\wt{\pi}$ denotes the $(\eps,\pi,\eqs{\ell})$-composite distribution on strings in $[k]^n$, we have
\begin{fact}  \label{fact:tv-mix} Let $(\distrb_\kappa)_{\kappa \in K}$ be a family of distributions on $\Omega^n$, let $\varsigma$ be a distribution on $K$, and let $\overline{\distrb}$ denote the associated mixture distribution, given by drawing $\kappa \sim \varsigma$ and then drawing from $\distrb_\kappa$.  Then
\[
\[
\dtv{\pi^{\otimes n}}{\wt{\pi}} \leq {\textstyle \sqrt{\frac{1}{\min(\pi)}-1}} \cdot \eps \sqrt{n}.
\dtv{\distra}{\overline{\distrb}} \leq \Ex_{\kappa \sim \varsigma}[\dtv{\distra}{\distrb_\kappa}].
\]
\]
\end{proposition}
\end{fact}
If we instead average Proposition~\ref{prop:prod-composite} over $\pi$, we can obtain:
 
\begin{proposition}  \label{prop:eqs-prod} Let $\nu$ be any distribution on $[k]$.  Writing $\wt{\mu}$ for the $(\eps, \eqs{k}, \nu)$-composite distribution on strings in $[k]^n$, we have
If we instead use this fact to average Proposition~\ref{prop:prod-composite} over $\prd$, we can obtain:
\begin{proposition}  \label{prop:eqs-prod} Let $\distrb$ be any distribution on $[k]$.  Writing $\distra$ for the $(\ppn, \eqs{k}, \distrb)$-composite distribution on strings in $[k]^n$, we have
\[
\[
\dtv{\eqs{k}^n}{\wt{\mu}} \leq (2k-1)\eps \sqrt{n}.
\dtv{\eqs{k}^n}{\distra} \leq (2k-1)\ppn \sqrt{n}.
\]
\]
\end{proposition}
\end{proposition}
\begin{proof}
\begin{proof}
Thinking of $\eqs{k}^m$ as the mixture of product distributions $\pi^{\otimes m}$, where $\pi$ is a random distribution on $[k]$, Fact~\ref{fact:tv-mix} and Proposition~\ref{prop:prod-composite} imply
Thinking of $\eqs{k}^m$ as the mixture of product distributions $\spac^{\otimes m}$, where $\spac$ is a random spacing on $[k]$, Fact~\ref{fact:tv-mix} and Proposition~\ref{prop:prod-composite} imply
\[
\[
\dtv{\eqs{k}^n}{\wt{\mu}} \leq \Ex_{\pi}\left[{\textstyle \sqrt{\frac{1}{\min(\pi)}-1}}\right] \cdot \eps \sqrt{n}.
\dtv{\eqs{k}^n}{\distra} \leq \Ex_{\spac}\left[{\textstyle \sqrt{\frac{1}{\min(\spac)}-1}}\right] \cdot \ppn \sqrt{n}.
\]
\]
We can upper-bound the expectation\noteryan{Undoubtedly someone has worked hard on this $-1/2$th moment of the least spacing before (Devroye '81 or '86 perhaps), but I think it's probably okay to do the following simple thing here} by  
We can upper-bound the expectation\noteryan{Undoubtedly someone has worked hard on this $-1/2$th moment of the least spacing before (Devroye '81 or '86 perhaps), but I think it's probably okay to do the following simple thing here} by  
\begin{multline*}
\begin{multline*}
\Ex_{\pi}\left[{\textstyle \sqrt{\frac{1}{\min(\pi)}}}\right] \quad=\quad \int_{0}^\infty \Pr_{\pi}\left[{\textstyle \sqrt{\frac{1}{\min(\pi)}}} \geq t\right]\,dt  
\Ex_{\spac}\left[{\textstyle \sqrt{\frac{1}{\min(\spac)}}}\right] \quad=\quad \int_{0}^\infty \Pr_{\spac}\left[{\textstyle \sqrt{\frac{1}{\min(\spac)}}} \geq t\right]\,dt  
\quad=\quad  \int_{0}^\infty \Pr_{\pi}[\min(\pi) \leq 1/t^2]\,dt \\
\quad=\quad  \int_{0}^\infty \Pr_{\spac}[\min(\spac) \leq 1/t^2]\,dt \\
\leq\quad k +  \int_{k}^\infty \Pr_{\pi}[\min(\pi) \leq 1/t^2]\,dt \quad\leq\quad k + \int_{k}^\infty (k(k-1)/t^2) \,dt \quad=\quad 2k-1,
\leq\quad k +  \int_{k}^\infty \Pr_{\spac}[\min(\spac) \leq 1/t^2]\,dt \quad\leq\quad k + \int_{k}^\infty (k(k-1)/t^2) \,dt \quad=\quad 2k-1,
\end{multline*}
\end{multline*}
where in the second-to-last step we used Proposition~\ref{prop:rand-min}.
where in the second-to-last step we used Proposition~\ref{prop:rand-min}.
\end{proof}
\end{proof}
Averaging now once more in the second component, we obtain the following:
Averaging now once more in the second component, we obtain the following:
\begin{proposition}  \label{prop:eqs-eqs} Let $2 \leq \ell \leq k$ and let $\wt{\mu}$ denote the $(\eps, \eqs{k}, \eqs{\ell})$-composite distribution on strings in $[k]^n$.  Then
\begin{proposition}  \label{prop:eqs-eqs} Let $2 \leq \ell \leq k$ and let $\distra'$ denote the $(\ppn, \eqs{k}, \eqs{\ell})$-composite distribution on strings in $[k]^n$.  Then
\[
\[
\dtv{\eqs{k}^n}{\wt{\mu}} \leq (2k-1) \eps \sqrt{n}.
\dtv{\eqs{k}^n}{\distra'} \leq (2k-1) \ppn \sqrt{n}.
\]
\]
\end{proposition}
\end{proposition}




Finally, it is inconvenient that in an $(\eps, \pi, \nu)$-composite distribution, the number of restricted coordinates $|J|$ can occasionally deviate significantly from its expectation $\eps n$.  We can prevent this with another small loss in total variation distance.
\begin{definition}  \label{def:r4r} Given $r \leq n/2$, define $\eps = 2r/n$.  We say that $J$ is an \emph{$[r,4r]$-random subset} of $[n]$ if $J$ is an $\eps$-random subset of $[n]$ conditioned on $r \leq |J| \leq 4r$.
\end{definition}
The following large-deviation bound is standard:\noteryan{Citation needed?}
\begin{fact}  \label{fact:dev} In Definition~\ref{def:r4r}, the probability that $r \leq |J| \leq 4r$ fails is at most $2\exp(-r/4)$.
\end{fact}


We can combine this fact with the previous propositions to get a master lemma for passing between distributions:\noteryan{I think it would be better if in this section we: 1. Had the equal-slices subsection. 2. Then had one more subsection which: a) begins with the statement of this lemma; then, b) says, ``Psst, reader, this lemma's proof is very boring.  We wouldn't be disappointed if you skipped reading it.''}
 
\begin{lemma}  \label{lem:distributions} Let $(\pi^m)$ and $(\nu^m)$ be distribution families.  Assume $2 \ln n \leq r \leq n/2$.  Let $J$ be an $[r,4r]$-random subset of $[n]$, let $x$ be drawn from $[k]^{\barJ}$ according to $\pi^{|\barJ|}$, and let $y$ be drawn from $[k]^J$ according to $\nu^{|J|}$.  The resulting distribution on $(x,y)$ has total variation distance from $\pi^n$ which can be bounded as follows:
We can now obtain the proof of Lemma~\ref{lem:distributions}:
\begin{enumerate}
 
\item (Product to equal-slices.) If $\pi^m = \pi^{\otimes m}$ and $\nu^m = \eqs{\ell}^m$ for $\ell \leq k$, the bound is
\begin{proof} The three statements in Lemma~\ref{lem:distributions} essentially follow from Propositions~\ref{prop:prod-eqs}, \ref{prop:eqs-prod}, and \ref{prop:eqs-eqs}, taking $\ppn = 2r/n$.  This would give bounds of $2{\textstyle \sqrt{\frac{1}{\min(\pi)}-1}} \cdot r / \sqrt{n}$, $(4k-2) \cdot r/\sqrt{n}$, and $(4k-2) \cdot r/\sqrt{n}$, respectively. However we need to account for conditioning on $r \leq \abs{J} \leq 4r$.  By Fact~\ref{fact:dev}, this conditioning increases the total variation distance by at most $2\exp(-r/4)$.  Using the lower bound $r \geq 2 \ln n$ from the lemma's hypothesis, this quantity is at most $2r/\sqrt{n}$, completing the proof.
\[
(2{\textstyle \sqrt{\frac{1}{\min(\pi)}-1}})+2) \cdot r / \sqrt{n}.
\]
\item (Equal-slices to product.) If $\pi^m = \eqs{k}^m$ and $\nu^m = \nu^{\otimes m}$, the bound is $4k \cdot r/\sqrt{n}$.
\item (Equal-slices to equal-slices.) \label{eqn:distrs-eqs-eqs} If $\pi^m = \eqs{k}^m$ and $\nu^m = \eqs{\ell}^m$ for $\ell \leq k$, the bound is $4k \cdot r/\sqrt{n}$.
\end{enumerate}
\end{lemma}
\begin{proof}
We apply Propositions~\ref{prop:prod-eqs}, \ref{prop:eqs-prod}, and \ref{prop:eqs-eqs} with $\eps = 2r/n$, but condition on $r \leq |J| \leq 4r$.  This increases the total variation distance by at most $2\gamma$, where $\gamma$ is the probability that $r \leq |J| \leq 4r$ fails. \textbf{ACTUALLY, JUST BY $\gamma$.} By Fact~\ref{fact:dev}, the increase is at most $4\exp(-r/4)$, which is at most $2 r / \sqrt{n}$ using the lower bound $r \geq 2 \ln n$.  The claimed bounds now follow.\noteryan{This is explained messily.}
\end{proof}
\end{proof}

Latest revision as of 12:25, 8 July 2009

\section{Passing between probability measures} \label{sec:measures}

The goal of this section is to work out bounds for the error arising when passing back and forth between $\unif_k$ and $\ens{k}$, as described in Section~\ref{sec:outline-dist}. Lemma~\ref{lem:distributions} below gives the bounds we need. The reader will not lose much by just reading its statement; the proof is just technical calculations.

Before stating Lemma~\ref{lem:distributions} we need some definitions.

\ignore{ \begin{definition} Given a set $A \subseteq [k]^n$ and a restriction $(J,x_\barJ)$, we write $A_{x_\barJ}$ for the subset of $[k]^{J}$ defined by $A_{x_\barJ} = \{y \in [k]^J : (x_{\barJ}, y_J) \in A\}$. \end{definition}}

\begin{definition} \label{def:r4r} For $0 \leq \ppn \leq 1$, we say that $J$ is a \emph{$\ppn$-random subset} of $[n]$ if $J$ is formed by including each coordinate $i \in [n]$ independently with probability $\ppn$. Assuming $r \leq n/2$, we say that $J$ is an \emph{$[r,4r]$-random subset} of $[n]$ if $J$ is a $\ppn$-random subset of $[n]$ conditioned on $r \leq \abs{J} \leq 4r$, with $\ppn = 2r/n$. \end{definition} \begin{definition} A \emph{distribution family} $(\distra^m)_{m \in \N}$ (over $[k]$) is a sequence of probability distributions, where $\distra^m$ is a distribution on $[k]^m$. In this paper the families we consider will either be the equal-(nondegenerate-)slices family $\distra^m = \ens{k}^m$ or $\distra^m = \eqs{k}^m$, or will be the product distributions based on a single distribution $\prd$ on $[k]$, $\distra^m = \prd^{\otimes m}$. \end{definition}


\begin{lemma} \label{lem:distributions} Let $(\distra^m)$ and $(\distrb^m)$ be distribution families. Assume $2 \ln n \leq r \leq n/2$. Let $J$ be an $[r,4r]$-random subset of $[n]$, let $x$ be drawn from $[k]^{\barJ}$ according to $\distra^{\abs{\barJ}}$, and let $y$ be drawn from $[k]^J$ according to $\distrb^{\abs{J}}$. The resulting distribution on the composite string $(x,y) \in [k]^n$ has total variation distance from $\distra^n$ which can be bounded as follows: \begin{enumerate} \item (Product to equal-slices.) \label{eqn:distrs-prd-eqs} If $\distra^m = \prd^{\otimes m}$ and $\distrb^m = \eqs{\ell}^m$ for $\ell \leq k$, the bound is \noteryan{You know, we only need this result for the uniform distribution, in which case we can bound the below by the simpler $2k \cdot r/\sqrt{n}$.} \[ (2{\textstyle \sqrt{\frac{1}{\min(\prd)}-1}})+2) \cdot r / \sqrt{n}. \] \item (Equal-slices to product.) \label{eqn:distrs-eqs-prd} If $\distra^m = \eqs{k}^m$ and $\distrb^m = \prd^{\otimes m}$, the bound is $4k \cdot r/\sqrt{n}$, independent of $\prd$. \item (Equal-slices to equal-slices.) \label{eqn:distrs-eqs-eqs} If $\distra^m = \eqs{k}^m$ and $\distrb^m = \eqs{\ell}^m$ for $\ell \leq k$, the bound is $4k \cdot r/\sqrt{n}$. \end{enumerate} \end{lemma}

Although Lemma~\ref{lem:distributions} involves the equal-slices distribution, one can convert to equal-nondegenerate-slices if desired using Proposition~\ref{prop:degen}.


Since $\eqs{k}^n$ is a mixture of product distributions (Proposition~\ref{prop:eqs-mix}), the main work in proving Lemma~\ref{lem:distributions} involves comparing product distributions.


\subsection{Comparing product distributions} \begin{definition} For $\distra$ and $\distrb$ probability distributions on $\Omega^n$, the \emph{$\chi^2$ distance} $\dchi{\pi}{\nu}$ is defined by \[ \dchi{\distra}{\distrb} = \sqrt{\Varx_{x \sim \distra}\left[\frac{\distrb[x]}{\distra[x]}\right]}. \] Note that $\dchi{\distra}{\distrb}$ is \emph{not} symmetric in $\distra$ and $\distrb$. \end{definition}

The $\chi^2$ distance is introduced to help us prove the following fact: \begin{proposition} \label{prop:mix-distance} Let $\prd$ be a distribution on $\Omega$ with full support; i.e., $\min(\pi) \neq 0$. Suppose $\prd$ is slightly mixed with $\distrb$, forming $\wh{\prd}$; specifically, $\wh{\prd} = (1-\ppn) \prd + \ppn \distrb$. Then the associated product distributions $\prd^{\otimes n}$, $\wh{\prd}^{\otimes n}$ on $\Omega^{n}$ satisfy \[ \dtv{\prd^{\otimes n}}{\wh{\prd}^{\otimes n}} \leq \dchi{\prd}{\distrb} \cdot \ppn \sqrt{n}. \] \end{proposition} \begin{proof} It is a straightforward consequence of Cauchy-Schwarz (see, e.g.~\cite[p.\ 101]{Rei89})\noteryan{This is the part using $\min(\prd) \neq 0$, by the way.} that \[ \dtv{\prd^{\otimes n}}{\wh{\prd}^{\otimes n}} \leq \dchi{\prd}{\wh{\prd}} \cdot \sqrt{n}, \] and the identity $\dchi{\prd}{\wh{\prd}} = \ppn \cdot \dchi{\prd}{\distrb}$ follows easily from the definitions. \end{proof} This can be bounded independently of $\distrb$, as follows: \begin{corollary} \label{cor:mix-distance} In the setting of Proposition~\ref{prop:mix-distance}, \[ \dtv{\prd^{\otimes n}}{\wh{\prd}^{\otimes n}} \leq \sqrt{{\textstyle \frac{1}{\min(\prd)}} - 1} \cdot \ppn \sqrt{n}, \] \end{corollary} \begin{proof} It is easy to check that the distribution $\distrb$ maximizing $\dchi{\prd}{\distrb}$ is the one putting all its mass on the $x$ minimizing $\prd[x]$. In this case one calculates $\dchi{\prd}{\distrb} = \sqrt{\frac{1}{\min(\pi)} - 1}$. \end{proof}



\subsection{Proof of Lemma~\ref{lem:distributions}}


\begin{definition} \label{def:compos-distr} Let $0 \leq \ppn \leq 1$ and let $(\distra^m)$, $(\distrb^m)$ be distribution families. Drawing from the \emph{$(\ppn, \distra, \distrb)$-composite distribution} on $[k]^n$ entails the following: $J$ is taken to be a $\ppn$-random subset of~$[n]$; $x$ is drawn from $[k]^{\barJ}$ according to $\distra^{\abs{\barJ}}$; and, $y$ is drawn from $[k]^J$ according to $\distrb^{\abs{J}}$. We sometimes think of this distribution as just being a distribution on composite strings $z = (x, y) \in [k]^n$. \end{definition}

Note that the distribution described in Lemma~\ref{lem:distributions} is very similar to the $(\ppn, \distra, \distrb)$-composite distribution, except that it uses an $[r, 4r]$-random subset rather than a $\ppn$-random subset. We can account for this difference with a standard Chernoff (large-deviation) bound:\noteryan{Citation needed?} \begin{fact} \label{fact:dev} If $J$ is a $\ppn$-random subset of $[n]$ with $\ppn = 2r/n$ as in Definition~\ref{def:r4r}, then $r \leq \abs{J} \leq 4r$ holds except with probability at most $2\exp(-r/4)$. \end{fact}

The utility of using $\ppn$-random subsets in Definition~\ref{def:compos-distr} is the following observation: \begin{fact} If $\prd$ and $\distrb$ are distributions on $[k]$, thought of also as product distribution families, then the $(\ppn, \prd, \distrb)$-composite distribution on $[k]^n$ is precisely the product distribution $\wh{\prd}^{\otimes n}$, where $\wh{\prd}$ is the mixture distribution $(1-\ppn)\prd + \ppn \distrb$ on $[k]$. \end{fact}

Because of this, we can use Corollary~\ref{cor:mix-distance} to bound the total variation distance between $\prd^{\otimes n}$ and a composite distribution. We conclude: \begin{proposition} \label{prop:prod-composite} Let $\prd$ and $\distrb$ be any distributions on $[k]$, thought of also as product distribution families. Writing $\wt{\prd}$ for the $(\ppn,\prd,\distrb)$-composite distribution on strings in $[k]^n$, we have \[ \dtv{\prd^{\otimes n}}{\wt{\prd}} \leq {\textstyle \sqrt{\frac{1}{\min(\prd)}-1}} \cdot \ppn \sqrt{n}. \] \end{proposition}

Recall that for any $\ell \leq k$, the equal-slices distribution $\eqs{\ell}^{m}$ on $m$ coordinates is a mixture of product distributions $\spac^{\otimes m}$ on $[k]^m$. We can therefore average Proposition~\ref{prop:prod-composite} over $\distrb$ to obtain: \begin{proposition} \label{prop:prod-eqs} If $\wt{\pi}$ denotes the $(\ppn,\pi,\eqs{\ell})$-composite distribution on strings in $[k]^n$, where $\ell \leq k$, then we have \[ \dtv{\pi^{\otimes n}}{\wt{\pi}} \leq {\textstyle \sqrt{\frac{1}{\min(\pi)}-1}} \cdot \ppn \sqrt{n}. \] \end{proposition} Here we have used the following basic bound, based on the triangle inequality: \begin{fact} \label{fact:tv-mix} Let $(\distrb_\kappa)_{\kappa \in K}$ be a family of distributions on $\Omega^n$, let $\varsigma$ be a distribution on $K$, and let $\overline{\distrb}$ denote the associated mixture distribution, given by drawing $\kappa \sim \varsigma$ and then drawing from $\distrb_\kappa$. Then \[ \dtv{\distra}{\overline{\distrb}} \leq \Ex_{\kappa \sim \varsigma}[\dtv{\distra}{\distrb_\kappa}]. \] \end{fact}

If we instead use this fact to average Proposition~\ref{prop:prod-composite} over $\prd$, we can obtain: \begin{proposition} \label{prop:eqs-prod} Let $\distrb$ be any distribution on $[k]$. Writing $\distra$ for the $(\ppn, \eqs{k}, \distrb)$-composite distribution on strings in $[k]^n$, we have \[ \dtv{\eqs{k}^n}{\distra} \leq (2k-1)\ppn \sqrt{n}. \] \end{proposition} \begin{proof} Thinking of $\eqs{k}^m$ as the mixture of product distributions $\spac^{\otimes m}$, where $\spac$ is a random spacing on $[k]$, Fact~\ref{fact:tv-mix} and Proposition~\ref{prop:prod-composite} imply \[ \dtv{\eqs{k}^n}{\distra} \leq \Ex_{\spac}\left[{\textstyle \sqrt{\frac{1}{\min(\spac)}-1}}\right] \cdot \ppn \sqrt{n}. \] We can upper-bound the expectation\noteryan{Undoubtedly someone has worked hard on this $-1/2$th moment of the least spacing before (Devroye '81 or '86 perhaps), but I think it's probably okay to do the following simple thing here} by \begin{multline*} \Ex_{\spac}\left[{\textstyle \sqrt{\frac{1}{\min(\spac)}}}\right] \quad=\quad \int_{0}^\infty \Pr_{\spac}\left[{\textstyle \sqrt{\frac{1}{\min(\spac)}}} \geq t\right]\,dt \quad=\quad \int_{0}^\infty \Pr_{\spac}[\min(\spac) \leq 1/t^2]\,dt \\ \leq\quad k + \int_{k}^\infty \Pr_{\spac}[\min(\spac) \leq 1/t^2]\,dt \quad\leq\quad k + \int_{k}^\infty (k(k-1)/t^2) \,dt \quad=\quad 2k-1, \end{multline*} where in the second-to-last step we used Proposition~\ref{prop:rand-min}. \end{proof} Averaging now once more in the second component, we obtain the following: \begin{proposition} \label{prop:eqs-eqs} Let $2 \leq \ell \leq k$ and let $\distra'$ denote the $(\ppn, \eqs{k}, \eqs{\ell})$-composite distribution on strings in $[k]^n$. Then \[ \dtv{\eqs{k}^n}{\distra'} \leq (2k-1) \ppn \sqrt{n}. \] \end{proposition}



We can now obtain the proof of Lemma~\ref{lem:distributions}:

\begin{proof} The three statements in Lemma~\ref{lem:distributions} essentially follow from Propositions~\ref{prop:prod-eqs}, \ref{prop:eqs-prod}, and \ref{prop:eqs-eqs}, taking $\ppn = 2r/n$. This would give bounds of $2{\textstyle \sqrt{\frac{1}{\min(\pi)}-1}} \cdot r / \sqrt{n}$, $(4k-2) \cdot r/\sqrt{n}$, and $(4k-2) \cdot r/\sqrt{n}$, respectively. However we need to account for conditioning on $r \leq \abs{J} \leq 4r$. By Fact~\ref{fact:dev}, this conditioning increases the total variation distance by at most $2\exp(-r/4)$. Using the lower bound $r \geq 2 \ln n$ from the lemma's hypothesis, this quantity is at most $2r/\sqrt{n}$, completing the proof. \end{proof}