Graham-Rothschild theorem: Difference between revisions
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Indeed, one can think of a combinatorial line in <math>[3]^n</math> as a string in <math>[4]^n</math> containing at least one 4, by thinking of 4 as the "wildcard". It is necessary to restrict to elements containing at least one 4; consider the coloring that colors a string black if it contains at least one 4, and white otherwise. | Indeed, one can think of a combinatorial line in <math>[3]^n</math> as a string in <math>[4]^n</math> containing at least one 4, by thinking of 4 as the "wildcard". It is necessary to restrict to elements containing at least one 4; consider the coloring that colors a string black if it contains at least one 4, and white otherwise. | ||
The Graham-Rothschild theorem and the [[Carlson-Simpson theorem]] have a common generalisation, | The Graham-Rothschild theorem and the [[Carlson-Simpson theorem]] have a common generalisation, [[Carlson's theorem]]. | ||
The k=1 case of the Graham-Rothschild theorem is [[Folkman's theorem]]. | |||
Latest revision as of 15:00, 16 February 2009
Graham-Rothschild theorem (k=3), Version 1: If all the combinatorial lines in [math]\displaystyle{ [3]^n }[/math] is partitioned into c color classes, and n is sufficiently large depending on c, m, then there is an m-dimensional combinatorial subspace of [math]\displaystyle{ [3]^n }[/math] such that all the combinatorial lines in this subspace have the same color.
This theorem implies the Hales-Jewett theorem. It has an alternate formulation:
Graham-Rothschild theorem (k=3), Version 2: If [math]\displaystyle{ [4]^n }[/math] is partitioned into c color classes, and n is sufficiently large depending on c, m, then there is an m-dimensional combinatorial subspace of [math]\displaystyle{ [4]^n }[/math], with none of the fixed positions equal to 4, such that all elements of this subspace that contain at least one 4 have the same color.
Indeed, one can think of a combinatorial line in [math]\displaystyle{ [3]^n }[/math] as a string in [math]\displaystyle{ [4]^n }[/math] containing at least one 4, by thinking of 4 as the "wildcard". It is necessary to restrict to elements containing at least one 4; consider the coloring that colors a string black if it contains at least one 4, and white otherwise.
The Graham-Rothschild theorem and the Carlson-Simpson theorem have a common generalisation, Carlson's theorem.
The k=1 case of the Graham-Rothschild theorem is Folkman's theorem.
