Excluding bichromatic vertices: Difference between revisions
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'''Theorem 1''' A 4-coloring of the unit plane cannot contain a bichromatic vertex (a vertex that can be colored in either of two colors while keeping the color of all other vertices fixed). | |||
'''Proof''' | |||
[[Category:Polymath16]] | [[Category:Polymath16]] | ||
Revision as of 11:00, 10 May 2018
Theorem 1 A 4-coloring of the unit plane cannot contain a bichromatic vertex (a vertex that can be colored in either of two colors while keeping the color of all other vertices fixed).
Proof
