Carlson-Simpson theorem: Difference between revisions
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Implies the [[coloring Hales-Jewett theorem]]. The k=2 version already implies [[Hindman's theorem]]. | Implies the [[coloring Hales-Jewett theorem]]. The k=2 version already implies [[Hindman's theorem]]. | ||
The Carlson-Simpson theorem and the [[Graham-Rothschild theorem]] have a common generalisation, | The Carlson-Simpson theorem and the [[Graham-Rothschild theorem]] have a common generalisation, [[Carlson's theorem]]. | ||
Both the Carlson-Simpson theorem and | Both the Carlson-Simpson theorem and Carlson's theorem are is used in the [[Furstenberg-Katznelson argument]]. | ||
Revision as of 18:14, 15 February 2009
Carlson-Simpson theorem (k=3): If [math]\displaystyle{ [3]^\omega := \bigcup_{n=0}^\infty [3]^n }[/math] is partitioned into finitely many color classes, then one of the color classes contains an infinite-dimensional combinatorial subspace, i.e. another copy of [math]\displaystyle{ [3]^\omega }[/math].
Implies the coloring Hales-Jewett theorem. The k=2 version already implies Hindman's theorem.
The Carlson-Simpson theorem and the Graham-Rothschild theorem have a common generalisation, Carlson's theorem.
Both the Carlson-Simpson theorem and Carlson's theorem are is used in the Furstenberg-Katznelson argument.
