DHJ(k) implies multidimensional DHJ(k): Difference between revisions

From Polymath Wiki
Jump to navigationJump to search
Line 1: Line 1:


==A weak multidimensional DHJ(k) implies DHJ(k)==
It is also true that a weak multidimensional DHJ(k) implies DHJ(k). We will show that the following statement is equivalent to DHJ(k):
“There is a constant, c < 1 that for every d there is an n that any c-dense subset of <math> [k]^n</math>  contains a d-dimensional subspace.”
We should show that the statement above implies DHJ(k). As before, write <math> [k]^n</math>  as <math> [k]^r\times[k]^s </math> , where s is much bigger than r. For each <math> y\in [k]^s</math> , define <math> \mathcal{A}_y</math>  to be <math> \{x\in[k]^r:(x,y)\in\mathcal{A}\}</math> . Let Y denote the set of <math> y\in [k]^s</math> such that <math>\mathcal{A}_y</math>  is empty. Suppose that <math> \mathcal{A} </math>  is large, line-free, and its density is <math> \delta =\Delta-\epsilon</math>  where <math> \Delta</math>  is the limit of density of line-free sets and <math> \epsilon < (1-c)\Delta</math> . We can also suppose that no <math> \mathcal{A}_y</math>  has density much larger than <math> \Delta</math>  as that would guarantee a combinatorial line. But then the density of Y is at most 1-c, so there is a c-dense set, <math> Z=[k]^s-Y</math>,  such that any element is a tail of some elements of <math> \mathcal{A}</math> . For every <math> y \in Z</math>  choose an <math> x\in [k]^r:(x,y)\in\mathcal{A}</math> . This x will be the colour of y. It gives a <math> [k]^r</math>  colouring on Z. By the initial condition Z contains arbitrary large subspaces, so by HJ(k) we get a line in <math> \mathcal{A}</math> .

Revision as of 20:11, 23 April 2009