Different upper and lower bound: Difference between revisions

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New page: If <math>N(a,b)</math> is the maximum length of a <math>\pm 1</math> sequence with the partial sums along its HAPs bounded below by <math>-a</math> and above by <math>b</math>, then: <mat...
 
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<math>N(2, 2) \geq 1124</math> (e.g [[the first 1124-sequence]])
<math>N(2, 2) \geq 1124</math> (e.g [[the first 1124-sequence]])
For the zero-based problem, see [http://gowers.wordpress.com/2010/01/06/erdss-discrepancy-problem-as-a-forthcoming-polymath-project/#comment-4822 this commend]


==Method==
==Method==

Revision as of 10:46, 9 January 2010

If [math]\displaystyle{ N(a,b) }[/math] is the maximum length of a [math]\displaystyle{ \pm 1 }[/math] sequence with the partial sums along its HAPs bounded below by [math]\displaystyle{ -a }[/math] and above by [math]\displaystyle{ b }[/math], then:

[math]\displaystyle{ N(a, b) = N(b, a) }[/math]

[math]\displaystyle{ N(0, b) = b }[/math] (everything must be [math]\displaystyle{ +1 }[/math])

[math]\displaystyle{ N(1, 1) = 11 }[/math] (there are [math]\displaystyle{ 4 }[/math] such sequences: choose [math]\displaystyle{ x_1 }[/math], and use the constraints [math]\displaystyle{ x_n +x_{2n} = 0 }[/math] and [math]\displaystyle{ x_1 + \ldots + x_{2n} = 0 }[/math] to determine the entries up to [math]\displaystyle{ 10 }[/math]; then choose [math]\displaystyle{ x_{11} }[/math])

[math]\displaystyle{ N(1, 2) = 41 }[/math] (there are [math]\displaystyle{ 4 }[/math] such sequences -- example below)

[math]\displaystyle{ N(1, 3) = 83 }[/math] (there are [math]\displaystyle{ 216 }[/math] such sequences -- example below)

[math]\displaystyle{ N(1, 4) = 131 }[/math] (there are [math]\displaystyle{ 87144 }[/math] such sequences -- example below)

[math]\displaystyle{ N(1,b)\lt \infty }[/math] (On a conjecture of Erdős and Čudakov)

[math]\displaystyle{ N(2, 2) \geq 1124 }[/math] (e.g the first 1124-sequence)

For the zero-based problem, see this commend

Method

Here should be a short description of the way the sequences was found. (The code(s) used should be further down this page.)

Status

Is the data still relevant (e.g. longest know)? Is the method still relevant, or have we found a better method? Is the program still running on a computer somewhere?

The sequence is the longest know sequence with discrepancy 2.

The data

[math]\displaystyle{ N(1, 2) = 41 }[/math] (there are [math]\displaystyle{ 4 }[/math] such sequences -- example below)

0 + - - + - + + - + + - - +
- + + - + - - - + - + + - -
+ + - + - + + - - - + - + +

[math]\displaystyle{ N(1, 3) = 83 }[/math] (there are [math]\displaystyle{ 216 }[/math] such sequences -- example below)

0 - + - + - + + - + + - - +
- + + - - + - - + - + + - +
+ + - - - + + - + + - - + -
+ - - + + - - + - + + + - +
- - - + + - + - + - - + - +
+ - + + - - + - + - - - + +


[math]\displaystyle{ N(1, 4) = 131 }[/math] (there are [math]\displaystyle{ 87144 }[/math] such sequences -- example below)

0 + - - + - + + - - + -
+ + - + + + + - - - + -
- + - + + - - + + + - -
- + + - + - + - - + + -
+ + - - + - - + - + + +
+ - - + - + - - + + + -
+ - - - - + + - - - + +
- - + + + + - - - - + +
- + - + + + + - - + + -
+ - - - + + - - - + - -
+ + + - + + - - + - - +

[math]\displaystyle{ N(2, 2) \geq 1124 }[/math]

--Alec 13:46, 9 January 2010 (UTC)

Relevant code

The code(s) (or a link to the code(s)) used to find this sequence should be posted here.