Lemma 7: Difference between revisions
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==Lemma 7:== | ==Lemma 7:== | ||
This proof is much longer than anticipated (and it's still not completed), | This proof is much longer than anticipated (and it's still not completed), so it will be split into six cases (with each case relying on the previous cases): | ||
[[Lemma 7.1]]: If there are two size 5 sets intersecting at 4 elements, then <math>\mathcal{A}</math> is Frankl's | [[Lemma 7.1]]: If there are two size 5 sets intersecting at 4 elements, then <math>\mathcal{A}</math> is Frankl's |
Latest revision as of 13:40, 3 December 2016
This page proves a lemma for the m=13 case of FUNC.
Lemma 7:
This proof is much longer than anticipated (and it's still not completed), so it will be split into six cases (with each case relying on the previous cases):
Lemma 7.1: If there are two size 5 sets intersecting at 4 elements, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's
Lemma 7.2: If there are two size 5 sets intersecting at 3 elements, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's
Lemma 7.3: If there are two size 5 sets intersecting at 2 elements, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's
Lemma 7.4: If there are two intersecting size 5 sets, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's
Lemma 7.5: If there are two size 5 sets, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's
Lemma 7.6: If there is a size 5 set, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's