Lemma 7: Difference between revisions

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==Lemma 7:==
==Lemma 7:==
This proof is much longer than anticipated (and it's still not completed), but it will be split into six cases (with each case relying on the previous cases):
This proof is much longer than anticipated (and it's still not completed), so it will be split into six cases (with each case relying on the previous cases):


[[Lemma 7.1]]: If there are two size 5 sets intersecting at 4 elements, then <math>\mathcal{A}</math> is Frankl's
[[Lemma 7.1]]: If there are two size 5 sets intersecting at 4 elements, then <math>\mathcal{A}</math> is Frankl's

Latest revision as of 13:40, 3 December 2016

This page proves a lemma for the m=13 case of FUNC.

Lemma 7:

This proof is much longer than anticipated (and it's still not completed), so it will be split into six cases (with each case relying on the previous cases):

Lemma 7.1: If there are two size 5 sets intersecting at 4 elements, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's

Lemma 7.2: If there are two size 5 sets intersecting at 3 elements, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's

Lemma 7.3: If there are two size 5 sets intersecting at 2 elements, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's

Lemma 7.4: If there are two intersecting size 5 sets, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's

Lemma 7.5: If there are two size 5 sets, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's

Lemma 7.6: If there is a size 5 set, then [math]\displaystyle{ \mathcal{A} }[/math] is Frankl's